5x^2+82x+32=0

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Solution for 5x^2+82x+32=0 equation: 



5x^2+82x+32=0

a = 5; b = 82; c = +32;
Δ = b2-4ac
Δ = 822-4·5·32
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-78}{2*5}=\frac{-160}{10}
=-16
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+78}{2*5}=\frac{-4}{10}
=-2/5
$

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